Matematika Sekolah Menengah Atas plis jawab dulu pertanyaan ku ​

plis jawab dulu pertanyaan ku ​

Nomor 2

[tex]3 \frac{1}{3} + \frac{4}{5} \\ \\ = \frac{10}{3} + \frac{4}{5} \\ \\ = \frac{(10 \times 5) + (3 \times 4)}{3 \times 5} \\ \\ = \frac{50 + 12}{15} \\ \\ = \frac{62}{15} \\ \\ = 4 \frac{2}{15} [/tex]

Jawaban C

[tex] \\ [/tex]

Nomor 3

[tex]4 \frac{3}{5} - \frac{2}{3} \\ \\ = \frac{23}{5} - \frac{2}{3} \\ \\ = \frac{69 - 10}{15} \\ \\ = \frac{59}{15} \\ \\ = 3 \frac{14}{15} [/tex]

Jawaban C

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Nomor 4

[tex]7 \frac{3}{4} - 4 \frac{2}{5} \\ \\ = \frac{31}{4} - \frac{22}{5} \\ \\ = \frac{155 - 88}{20} \\ \\ = \frac{67}{20} \\ \\ = 3 \frac{7}{20} [/tex]

Jawaban D

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Nomor 5

[tex]5 \frac{3}{5} + 2 \frac{3}{4} \\ \\ = \frac{28}{5} + \frac{11}{4} \\ \\ = \frac{112 + 55}{20} \\ \\ = \frac{167}{20} \\ \\ = 8 \frac{7}{20} [/tex]

Jawaban A

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Nomor 6

[tex] \frac{2}{3} \cdots \frac{4}{9} \\ \tiny(9 \times 2) \cdots \: (3 \times 4) \\ \tiny18 > 12[/tex]

Jawaban B

[tex] \\ [/tex]

Nomor 7

[tex] \frac{1}{3} \: \: \frac{1}{4} \: \: \frac{2}{3} \: \: \frac{3}{4} \: \: \frac{3}{6} \: \: \frac{5}{6} \\ \\ \frac{8}{24} \: \: \frac{6}{24} \: \: \frac{16}{24} \: \: \frac{18}{24} \: \: \frac{12}{24}\: \:\frac{20}{24}\\\\ \frac{20}{24}>\frac{18}{24}> \frac{16}{24} > \frac{12}{24}> \frac{8}{24}>\frac{6}{24}\\\\= \bold{ \frac{5}{6}; \frac{3}{4}; \frac{2}{3}; \frac{3}{6} ; \frac{1}{3} ; \frac{1}{4} }[/tex]

Jawaban B

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nt: No. 8, 9, dan 10 kalimat soal kepotong

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